1.- Un émbolo de 40 cm de diámetro avanza 5 cm bajo una presión de 10 atm. ¿Cuántas calorías corresponderán a este trabaj
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![SOLVED: Convert 0.121 kcal to L atm; (1 L atm = 101.3 J; 1 cal = 4.184 J) Select one: a. 5.00 L atm b. 4.998 L atm c. 4.99 x 10^-3 atm d. 5.00 x 10^-3 L atm e. 4.99 L atm SOLVED: Convert 0.121 kcal to L atm; (1 L atm = 101.3 J; 1 cal = 4.184 J) Select one: a. 5.00 L atm b. 4.998 L atm c. 4.99 x 10^-3 atm d. 5.00 x 10^-3 L atm e. 4.99 L atm](https://cdn.numerade.com/ask_images/948e7b1dc1784895bb75bf2e0d3bb70b.jpg)
SOLVED: Convert 0.121 kcal to L atm; (1 L atm = 101.3 J; 1 cal = 4.184 J) Select one: a. 5.00 L atm b. 4.998 L atm c. 4.99 x 10^-3 atm d. 5.00 x 10^-3 L atm e. 4.99 L atm
![SOLVED: Conversion Factors: 1 gal = 231 in³ (exact) 1 atm = 760 torr (exact) 1 cm³ = 1 mL (exact) 1 lb = 453.59237 g (exact) 2.54 cm = 1 in ( SOLVED: Conversion Factors: 1 gal = 231 in³ (exact) 1 atm = 760 torr (exact) 1 cm³ = 1 mL (exact) 1 lb = 453.59237 g (exact) 2.54 cm = 1 in (](https://cdn.numerade.com/ask_images/98c41ed6b3e54a558ac16356f85004bd.jpg)
SOLVED: Conversion Factors: 1 gal = 231 in³ (exact) 1 atm = 760 torr (exact) 1 cm³ = 1 mL (exact) 1 lb = 453.59237 g (exact) 2.54 cm = 1 in (
![Principios de Termodinamica aplicados a las ciencias farmaceuticas - Práctica N° CALOR Y TRABAJO - Studocu Principios de Termodinamica aplicados a las ciencias farmaceuticas - Práctica N° CALOR Y TRABAJO - Studocu](https://d20ohkaloyme4g.cloudfront.net/img/document_thumbnails/8917aae5502d7566f662485f973be045/thumb_1200_1553.png)
Principios de Termodinamica aplicados a las ciencias farmaceuticas - Práctica N° CALOR Y TRABAJO - Studocu
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